1. A specimen has mass 100 g and molar mass 80 g mol⁻¹. The number of moles present is:
- 0.8 mol
- 1.25 mol
- 2.5 mol
- 8000 mol
Show answer and explanation
Answer: (B) 1.25 mol
n = mass/molar mass = 100/80 = 1.25 mol.
Quick tip: Moles = mass ÷ molar mass.
111 questions on this topic of Some Basic Concepts in Chemistry (NEET 2027 syllabus). Here are 12; tap one to see its answer and explanation.
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Answer: (B) 1.25 mol
n = mass/molar mass = 100/80 = 1.25 mol.
Quick tip: Moles = mass ÷ molar mass.
Answer: (D) Cannot determine atoms
22.4L = 1 mole molecules. Atoms = moles × atomicity. Atomicity varies per gas.
Quick tip: 22.4L = 1 mole molecules. But atoms depend on atomicity of the specific gas!
NCERT Class 11, Chapter 1, page 13
Answer: (D) 82.4 %
% = (mass of nitrogen in one mole / molar mass) × 100 = 14/17 × 100 = 82.4%.
Answer: (D) 3.01 × 10²³
n = 20/40 = 0.5 mol; molecules = n × Nₐ = 3.01 × 10²³.
Answer: (A) 6.5 mol
n = mass / molar mass = 130/20 = 6.5 mol.
Quick tip: n = m/M. Mass on top.
NCERT Class 11, Chapter 1
Answer: (D) 0.1 mol
Number of moles = given mass/molar mass: n = 4/40 = 0.1 mol.
Answer: (A) 1.3 mol
n = mass/molar mass = 130/100 = 1.3 mol.
Quick tip: Moles = mass ÷ molar mass.
Answer: (A) 0.8 mol
n = mass / molar mass = 80/100 = 0.8 mol.
Quick tip: n = m/M. Mass on top.
NCERT Class 11, Chapter 1
Answer: (C) 5 mol
Number of moles = given mass/molar mass: n = 490/98 = 5 mol.
Answer: (B) 0.1 mol
Number of moles = given mass/molar mass: n = 9.8/98 = 0.1 mol.
Answer: (B) 6.02 × 10²²
n = 4/40 = 0.1 mol; molecules = n × Nₐ = 6.02 × 10²².
Answer: (C) 1.2 × 10²⁴
n = 80/40 = 2 mol; molecules = n × Nₐ = 1.2 × 10²⁴.