1. A capillary tube of radius r = 0.2 mm is dipped vertically into a beaker of pure water (density = 1000 kg/m³, contact angle θ = 0°). Water rises to a height of 7.5 cm. Taking g = 10 m/s², the surface tension of water calculated from this experiment is:
- 0.015 N/m
- 0.0375 N/m
- 0.150 N/m
- 0.075 N/m
Show answer and explanation
Answer: (D) 0.075 N/m
Surface tension is given by T = (r h ρ g) / (2 cos θ). Substituting r = 0.2 × 10⁻³ m, h = 7.5 × 10⁻² m, ρ = 1000 kg/m³, g = 10 m/s², and cos 0° = 1 gives T = (0.2 × 10⁻³ × 7.5 × 10⁻² × 1000 × 10) / 2 = 0.15 / 2 = 0.075 N/m.