194 questions on Physics and Measurement for NEET 2027, 1 of them from previous NEET papers. Below are 15 to try; tap a question to see its answer and explanation.
Free with a Google sign-in; NEET Daily needs no sign-in at all.
Answer: (B) [ML²T⁻¹]
Angular momentum L = mvr = [M][LT⁻¹][L] = [ML²T⁻¹]. Same dimensions as Planck's constant h.
Quick tip: Angular momentum = Planck's constant in dimensions. Both are [ML²T⁻¹].
NCERT Class 11, Chapter 2, page 22
Answer: (A) 0.01 mm
Least count = pitch / number of circular-scale divisions = 1/100 = 0.01 mm.
Quick tip: Least count = pitch ÷ circular divisions.
NCERT Class 11
Answer: (D) 7.5 %
Relative errors add, each multiplied by its power, even for a quantity in the denominator: ΔZ/Z = 2(ΔA/A) + 3(ΔB/B) + ΔC/C = 2×1.5 + 3×0.5 + 3 = 7.5%.
Quick tip: Multiply each percentage error by its power and always add, never subtract.
NCERT Class 11
Answer: (D) [F A² V⁻⁴]
Let Y = Fᵃ Aᵇ Vᶜ. Dimensions of Y (stress) are [M L⁻¹ T⁻²]. [F] = [M L T⁻²], [A] = [L T⁻²], [V] = [L T⁻¹]. Thus, [M L⁻¹ T⁻²] = [M L T⁻²]ᵃ [L T⁻²]ᵇ [L T⁻¹]ᶜ = Mᵃ Lᵃ⁺ᵇ⁺ᶜ T⁻²ᵃ⁻²ᵇ⁻ᶜ. Comparing powers gives a = 1; a + b + c = -1; -2a - 2b - c = -2. Solving yields b = 2 and c = -4. Hence, [Y] = [F A² V⁻⁴].
Answer: (C) 3 %
Maximum relative errors add for products and quotients, weighted by powers: 2×1% + 1×1% = 3%.
Answer: (B) Statement I is correct but Statement II is incorrect
Statement I is correct because systematic errors arise from known flaws in instruments or techniques and can be eliminated or reduced by proper calibration and better methods. Statement II is incorrect because the least count is the smallest value that can be measured by the instrument; it is related to the resolution/instrumental error, not the maximum possible random error, which can be larger or smaller depending on external variations and operator inconsistency.
Answer: (C) 1.0 × 10⁵ kg
Force = Mass × Acceleration = M L T⁻². Therefore, M = Force × T² / L. Substituting given values: M = (100 N) × (100 s)² / (10 m) = 100 × 10000 / 10 = 100,000 kg = 1.0 × 10⁵ kg.
Answer: (D) Energy
By the principle of homogeneity, [a/V²] = [P], so [a] = [P][V²] = [M L⁻¹ T⁻²][L⁶] = [M L⁵ T⁻²]. Also, [b] = [V] = [L³]. Thus, [a/b] = [M L⁵ T⁻²] / [L³] = [M L² T⁻²], which is the dimension of energy.
Answer: (C) 9 %
Relative errors add, each multiplied by its power, even for a quantity in the denominator: ΔZ/Z = 2(ΔA/A) + 3(ΔB/B) + ΔC/C = 2×2 + 3×1 + 2 = 9%.
Quick tip: Multiply each percentage error by its power and always add, never subtract.
NCERT Class 11
Answer: (D) [M⁻¹ L³ T⁻²]
From Newton's law of gravitation, F = G m₁ m₂ / r², so G = F r² / (m₁ m₂). Substituting dimensions, [G] = [M L T⁻²][L²] / [M²] = [M⁻¹ L³ T⁻²].
Answer: (C) Latent heat
Latent heat L is defined as heat per unit mass (Q/m). Its dimensional formula is [M L² T⁻²] / [M] = [M⁰ L² T⁻²]. Specific heat capacity has dimensions [M⁰ L² T⁻² K⁻¹].
Answer: (C) [M L⁰ T⁻³]
Solar constant has units of energy per unit area per second (W m⁻²). Its dimensional formula is [M L² T⁻²] / ([L²] [T]) = [M L⁰ T⁻³].
Answer: (A) kg·m²·s⁻²·mol⁻¹·K⁻¹
Since R has the unit J·mol⁻¹·K⁻¹ and 1 Joule = 1 N·m = 1 kg·m²·s⁻², the base unit representation of R is kg·m²·s⁻²·mol⁻¹·K⁻¹.
Answer: (D) 1/2, 0, 1/2
Dimensional formula for velocity is [L T⁻¹]. Writing [L T⁻¹] = [L]ᵃ [M L⁻³]ᵇ [L T⁻²]ᶜ = [Mᵇ L^(a - 3b + c) T^(-2c)]. Equating exponents gives b = 0, -2c = -1 ⇒ c = 1/2, and a - 0 + 1/2 = 1 ⇒ a = 1/2.
Answer: (C) All terms on both sides have the same dimensions
Only quantities with the same dimensions can be added, subtracted or equated, so every term in a correct equation must have identical dimensions.
NCERT Class 11