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Concentration units: NEET MCQs with answers

63 questions on this topic of Solutions (NEET 2027 syllabus). Here are 12; tap one to see its answer and explanation.

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easy

1. 11.7 g of NaCl (M = 58.5 g/mol) is dissolved in 100 g of water. The molality of the solution is:

  1. 0.002 mol/kg
  2. 2 mol/kg
  3. 0.02 mol/kg
  4. 0.117 mol/kg
Show answer and explanation

Answer: (B) 2 mol/kg

Moles = 11.7/58.5 = 0.2. Molality = 0.2/(100/1000 kg) = 2 mol/kg.

hard

2. A solution is diluted to twice its original volume at constant temperature. Which quantity for a non-volatile solute is halved?

  1. Number of moles of solute
  2. Mole fraction of solvent exactly
  3. Molarity of solute
  4. Molar mass of solute
Show answer and explanation

Answer: (C) Molarity of solute

Dilution does not change solute moles or molar mass. Molarity M=n/V, so doubling volume halves molarity.

Quick tip: Separate extensive amount of solute from concentration.

NCERT Class 12, Chapter 2, page 42

easy

3. 2 mol of solute is present in 500 mL of solution. The molarity is:

  1. 1 M
  2. 40 M
  3. 0.25 M
  4. 4 M
Show answer and explanation

Answer: (D) 4 M

Unit check: Convert volume to litres: V = 0.5 L. M = n/V = 2/0.5 = 4 M.

easy

4. 29.3 g of NaCl (M = 58.5 g/mol) is dissolved in 100 g of water. The molality of the solution is:

  1. 0.292 mol/kg
  2. 5 mol/kg
  3. 0.05 mol/kg
  4. 0.005 mol/kg
Show answer and explanation

Answer: (B) 5 mol/kg

Moles = 29.3/58.5 = 0.5. Molality = 0.5/(100/1000 kg) = 5 mol/kg.

easy

5. A solution has concentration 2 mmol/L. Express this in mol/L:

  1. 2 mol/L
  2. 2000 mol/L
  3. 0.002 mol/L
  4. 0.02 mol/L
Show answer and explanation

Answer: (C) 0.002 mol/L

Unit check: 1 mmol = 10⁻³ mol, so 2 mmol/L = 0.002 mol/L.

easy

6. 2 mol of solute is present in 100 mL of solution. The molarity is:

  1. 20 M
  2. 0.2 M
  3. 0.05 M
  4. 200 M
Show answer and explanation

Answer: (A) 20 M

Unit check: Convert volume to litres: V = 0.1 L. M = n/V = 2/0.1 = 20 M.

easy

7. 18 g of glucose (M = 180 g/mol) is dissolved in 200 g of water. The molality of the solution is:

  1. 0.02 mol/kg
  2. 0.5 mol/kg
  3. 0.09 mol/kg
  4. 5 × 10⁻⁴ mol/kg
Show answer and explanation

Answer: (B) 0.5 mol/kg

Moles = 18/180 = 0.1. Molality = 0.1/(200/1000 kg) = 0.5 mol/kg.

easy

8. 0.2 mol of solute is present in 200 mL of solution. The molarity is:

  1. 1 M
  2. 0.5 M
  3. 0.04 M
  4. 10 M
Show answer and explanation

Answer: (A) 1 M

Unit check: Convert volume to litres: V = 0.2 L. M = n/V = 0.2/0.2 = 1 M.

easy

9. 1 mol of solute is present in 1 L of solution. The molarity is:

  1. 1 M
  2. 0.5 M
  3. 10 M
  4. 1.5 M
Show answer and explanation

Answer: (A) 1 M

Unit check: Convert volume to litres: V = 1 L. M = n/V = 1/1 = 1 M.

easy

10. 11.7 g of NaCl (M = 58.5 g/mol) is dissolved in 250 g of water. The molality of the solution is:

  1. 8 × 10⁻⁴ mol/kg
  2. 0.8 mol/kg
  3. 0.0468 mol/kg
  4. 0.05 mol/kg
Show answer and explanation

Answer: (B) 0.8 mol/kg

Moles = 11.7/58.5 = 0.2. Molality = 0.2/(250/1000 kg) = 0.8 mol/kg.

easy

11. 0.5 mol of solute is present in 200 mL of solution. The molarity is:

  1. 0.4 M
  2. 2.5 M
  3. 25 M
  4. 0.1 M
Show answer and explanation

Answer: (B) 2.5 M

Unit check: Convert volume to litres: V = 0.2 L. M = n/V = 0.5/0.2 = 2.5 M.

easy

12. A solution has concentration 10 mmol/L. Express this in mol/L:

  1. 10000 mol/L
  2. 0.1 mol/L
  3. 10 mol/L
  4. 0.01 mol/L
Show answer and explanation

Answer: (D) 0.01 mol/L

Unit check: 1 mmol = 10⁻³ mol, so 10 mmol/L = 0.01 mol/L.

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